1.

In chemical analysis, it is found that in 10 g iron chloride, 3.438 g iron and 6.650 g chlorine are present. Calculate the empirical formula of iron chloride. (Fe = 55.8, Cl= 35.5)

Answer»

Percentage of iron = \(\frac{3.438}{10}\) × 100 = 34.38%
Percentage of Chlorine = \(\frac{6.65}{10}\) × 100 = 66.5%

Element%Atomic massRelative ratioSimplest ratio
Fe34.3855.834.38/55.8 = 0.60.6/0.6 = 1
Cl66.535.566.5/35.5 = 1.81.8/0.6 = 3

Thus, the empirical formula of iron chloride is FeCl3


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