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in chlorine.^(35)CIand .^(37) CI isin3:1ratiocalculatechargeatomicmass. |
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Answer» Solution :three `.^(35) CI` and one `.^(37)CI` totalfour CI massof fourCI= 3 (35)+ 1 (37) 142 AMU atomicmass ofCI` =(142)/( 4) = 35.5`amu |
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