1.

In corrundum, oxide ions are arranged in hexagonal close packing and aluminium ions occupy two-third of the octahedral voids. What is the formula fo corrundum ?

Answer»


SOLUTION : SUPPOSE oxideions = n . Then octahedral voids = n Hence,` Al^(3+) " ions"= 2/3 xx n = (2n)/3`
RATIO` Al^(3+): O^(2-)= (2n)/ 3 : n = 2: 3`FORMULA is ` Al_(2)O_(3)` \


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