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In corundum, oxide ions are arranged in hexagonal close packing and aluminium ionsa occpy tow-third of the octaheral voids. What is the formula of corrundum ? . |
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Answer» Number of oxides per unit cell = 6 Number of octahedral voids per unit cell=6 Number of `Al^(+3)` ions in octahedral voids=`(6xx2)/3=4` `therefore Al^(+3) : O^(-2)` 4 :6 or 2 :3 Hence, formula is `Al_2O_3` |
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