In cricket match, a bowler throws a ball of 0.5 kg with a speed of 20 m/s. When a batsman swings the bat the ball strikes with the bat normal to it, and returns in opposite direction with speed of 30 m/s. If the time of contact of the ball with the bat is 0.1s, then the force acting on the bat is......N.

In cricket match, a bowler throws a ball of 0.5 kg with a speed of 20

1.	In cricket match, a bowler throws a ball of 0.5 kg with a speed of 20 m/s. When a batsman swings the bat the ball strikes with the bat normal to it, and returns in opposite direction with speed of 30 m/s. If the time of contact of the ball with the bat is 0.1s, then the force acting on the bat is......N.
Answer» 50 125 250 25 Solution :change in momentum of BALL `DELTAP=p_(2)-p_(1)` `=m(v_(2)-v_(1))` `=0.5(-3-20)` `=-0.5xx50` `=-25kgm//s` Momentum gained by BAT `Deltap=+25kgm//s` `therefore` The force acting on bat `F=(Deltap)/(Deltat)=(25)/(0.1)` `=250N`