In Δ ABC, AB=10 cm, ∠A=40∘, ∠B=80∘. The area of triangle ABC

1.	In Δ ABC, AB=10 cm, ∠A=40∘, ∠B=80∘. The area of triangle ABC will be equal to [tan 40∘=0.83tan 80∘=5.6]
Answer» In $Δ A B C, A B = 10 c m, ∠ A = 40^{\circ}, ∠ B = 80^{\circ} .$ The area of triangle ABC will be equal to $[\begin{matrix} t a n 40^{\circ} = 0.83 t a n 80^{\circ} = 5.6 \end{matrix}]$

In Δ ABC, AB=10 cm, ∠A=40∘, ∠B=80∘. The area of triangle ABC will be equal to [tan 40∘=0.83tan 80∘=5.6]

Answer»

In $Δ A B C, A B = 10 c m, ∠ A = 40^{\circ}, ∠ B = 80^{\circ} .$ The area of triangle ABC will be equal to

$[\begin{matrix} t a n 40^{\circ} = 0.83 t a n 80^{\circ} = 5.6 \end{matrix}]$

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In Δ ABC, AB=10 cm, ∠A=40∘, ∠B=80∘. The area of triangle ABC will be equal to [tan 40∘=0.83tan 80∘=5.6]

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