In Δ ABC, AB=15 cm, ∠ A=30∘, ∠ B=130∘. The area of the triang

1.	In Δ ABC, AB=15 cm, ∠ A=30∘, ∠ B=130∘. The area of the triangle will be equal to [Tan 30∘=0.57Tan 50∘=1.2]
Answer» In $Δ A B C, A B = 15 c m, ∠ A = 30^{\circ}, ∠ B = 130^{\circ} .$ The area of the triangle will be equal to $[\begin{matrix} T a n 30^{\circ} = 0.57 T a n 50^{\circ} = 1.2 \end{matrix}]$

In Δ ABC, AB=15 cm, ∠ A=30∘, ∠ B=130∘. The area of the triangle will be equal to [Tan 30∘=0.57Tan 50∘=1.2]

Answer»

In $Δ A B C, A B = 15 c m, ∠ A = 30^{\circ}, ∠ B = 130^{\circ} .$ The area of the triangle will be equal to $[\begin{matrix} T a n 30^{\circ} = 0.57 T a n 50^{\circ} = 1.2 \end{matrix}]$

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In Δ ABC, AB=15 cm, ∠ A=30∘, ∠ B=130∘. The area of the triangle will be equal to [Tan 30∘=0.57Tan 50∘=1.2]

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