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In Δ ABC ∠B = ∠C and ray AX bisects the exterior angle ∠DAC. If ∠DAX =70°, then ∠ACB =A. 35°B. 90°C. 70°D. 55° |
Answer» AX bisects ∠DAC ∠CAD = 2 x ∠DAC ∠CAD = 2 x 70° = 140° By exterior angle theorem, ∠CAD = ∠B + ∠C 140° = ∠C + ∠C (Therefore, ∠B = ∠C) 140° = 2∠C ∠C = 70° Therefore, ∠C = ∠ACB = 70° |
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