In Δ ABC, if ∠A = 100° AD bisects ∠A and AD⊥BC. Then, ∠B =A. – InterviewSolution

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In Δ ABC, if ∠A = 100° AD bisects ∠A and AD⊥BC. Then, ∠B =A. 50°B. 90°C. 40°D. 100°

Answer»

Given,

AD perpendicular to BC

∠A = 100°

In ΔADB

∠ADB + ∠B + ∠DAC = 180°

90° + ∠B + \(\frac{1}{2}\)∠A = 180°

∠B + \(\frac{1}{2}\) x 100° = 180° – 90°

∠B + 50° = 90°

∠B = 40°

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