In ΔABC,∠A is obtuse, PB⊥AC and QC⊥AB prove that: (i) AB×AQ=AC×AP (ii) BC2=(AC×CP+AB×BQ)

In ΔABC,∠A is obtuse, PB⊥AC and QC⊥AB prove that: (i) AB×AQ=AC

1.	In ΔABC,∠A is obtuse, PB⊥AC and QC⊥AB prove that: (i) AB×AQ=AC×AP (ii) BC2=(AC×CP+AB×BQ)
Answer» In $Δ A B C, ∠ A$ is obtuse, $P B ⊥ A C$ and $Q C ⊥ A B$ prove that: (i) $A B \times A Q = A C \times A P$ (ii) $B C^{2} = (A C \times C P + A B \times B Q)$

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In ΔABC,∠A is obtuse, PB⊥AC and QC⊥AB prove that: (i) AB×AQ=AC×AP (ii) BC2=(AC×CP+AB×BQ)

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