In ΔABC, ∠ACB=90∘, AB = C units, BC = a units, AC = b units, CD i

1.	In ΔABC, ∠ACB=90∘, AB = C units, BC = a units, AC = b units, CD is perpendicular to AB and CD = p units. Then 1p2=
Answer» In $Δ A B C$ , $∠ A C B = 90^{\circ}$ , AB = C units, BC = a units, AC = b units, CD is perpendicular to AB and CD = p units. Then $\frac{1}{p^{2}} =$

In ΔABC, ∠ACB=90∘, AB = C units, BC = a units, AC = b units, CD is perpendicular to AB and CD = p units. Then 1p2=

Answer»

In $Δ A B C$ , $∠ A C B = 90^{\circ}$ , AB = C units, BC = a units, AC = b units, CD is perpendicular to AB and CD = p units. Then $\frac{1}{p^{2}} =$

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In ΔABC, ∠ACB=90∘, AB = C units, BC = a units, AC = b units, CD is perpendicular to AB and CD = p units. Then 1p2=

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