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In ΔABC, D and E are the mid-points of AB and AC respectively. Find the ratio of the areas of ΔADE and ΔABC. |
Answer» We have, D and E as the midpoint of AB and AC So, according to the midpoint therom DE||BC and DE = 1/2 BC……………..(i) In ΔADE and ΔABC ∠A = ∠A (Common) ∠ADE = ∠B (Corresponding angles) Then, ΔADE ~ ΔABC (By AA similarity) By area of similar triangle theorem Area ΔADE/ Area ΔABC = DE2/BC2 Or, (1/2BC)2/(BC)2 Or, 1/4 |
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