In ΔABC,\(\overline{AD}\) , \(\overline{BE}\) are medians \(\over – InterviewSolution

InterviewSolution

1.	In ΔABC,\(\overline{AD}\) , \(\overline{BE}\) are medians \(\overline{BE}\) ∥ \(\overline{DF}\)To prove CF = 1/4 AC it was written as In ΔABC ‘D’ is the mid-point of \(\overline{BC}\) and BE \|\| DF. As per triangle mid-point of \(\overline{CE}\).CF = 1/2 CEWhich of the following is the next step ? A) CF = 1/2 AC B) 2CF = CE C) CF = 1/2(1/2 AC) D) 4CF = AC
Answer» Correct option is B) 2CF = CE

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