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In damped oscillatory motion a block of mass 200g is suspended to a spring of force constant 90 N//m in a medium and damping constant is 40g//s. Find time period of oscillation |
Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> ,= 200g= 0.2 kg force constant <a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a> = `90N//m` damping constant `b = 40g//s =0.04 kg//s`. <br/> `sqrt(km)= sqrt(<a href="https://interviewquestions.tuteehub.com/tag/90-341351" style="font-weight:bold;" target="_blank" title="Click to know more about 90">90</a> xx 0.2)= sqrt(18) kg//s` <br/> Here `b lt lt sqrt(km)`<br/> <a href="https://interviewquestions.tuteehub.com/tag/time-19467" style="font-weight:bold;" target="_blank" title="Click to know more about TIME">TIME</a> period `T= 2pisqrt((m)/(k))= 2pisqrt((0.2)/(90))= 0.3s`</body></html> | |