1.

In `DeltaABC`, with usual notations, `(bsinB-c sin C)/(sin(B-C))=`. . . .A. bB. `a+b+c`C. aD. c

Answer» Correct Answer - C
We have, `s s (b "sin" B - c "sin" C)/("sin" (B - C))`
`(k "sin" B "sin" B - k "sin" C "sin" C)/("sin"(B - C))`
`(k"sin"^(2) B - "sin"^(2)C)/("sin" (B - C))`
`= k sin (B + C)`
`= k "sin" (180^(@) - A)`
`= K "sin" A = a`


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