In double slit experiment using light of wavelength `600 nm`, the angular width of a fringe formed on a distant screen is `0.1^(@)`. What is the spacing between the two slits ?

In double slit experiment using light of wavelength `600 nm`, the angu

1.	In double slit experiment using light of wavelength `600 nm`, the angular width of a fringe formed on a distant screen is `0.1^(@)`. What is the spacing between the two slits ?
Answer» Wavelength of light used, `lambda=6000 nm =600 xx10^(-9)` Angular width of fringe, `theta=0.1^(@)=0.1xx(pi)/(180)=(3.14)/(1800)"rad"` Angular width of a fringe is related to slit spacing (d) as : `theta=(lambda)/(d)` `d=(lambda)/(theta)` `=(600xx10^(-9))/((3.14)/(1800))=3.44xx10^(-4)m` Therefore, the spacing between the slits is `3.44xx10^(-4)m.`

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In double slit experiment using light of wavelength `600 nm`, the angular width of a fringe formed on a distant screen is `0.1^(@)`. What is the spacing between the two slits ?

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