In double-slit experiment using light of wavelength 600 nm, the angular width of a fring formed on a distant screen is `0.1^(@)`. What is the spacing between the two slits ?

In double-slit experiment using light of wavelength 600 nm, the angula

1.	In double-slit experiment using light of wavelength 600 nm, the angular width of a fring formed on a distant screen is `0.1^(@)`. What is the spacing between the two slits ?
Answer» Here, `lambda=600nm=6xx10^(-7)m, theta=0.1^(@)=(0.1^@))/(180^(@))xxpirad,d=?` Since `theta=(lambda)/(d) Rightarrow d=(lambda)/(theta)=(6xx10^(-7)xx180^(@))/(0.1^(@)xxpi)=3.43xx10^(-4)m`

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In double-slit experiment using light of wavelength 600 nm, the angular width of a fring formed on a distant screen is `0.1^(@)`. What is the spacing between the two slits ?

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