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In ΔPQR, PQ = 5 cm, QR = 12 cm and PR = 13 cm, then PQR is A) an acute angled triangleB) a right angled triangle C) an obtuse angled triangle D) an equilateral triangle |
Answer» Correct option is (B) a right angled triangle \(\because5^2+12^2\) = 25+144 = 169 \(=13^2\) \(\therefore PQ^2+QR^2=PR^2\) which is a condition that \(\triangle PQR\) is a right angled triangle. (By converse of Pythagoras theorem) B) a right angled triangle |
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