In Duma's method, 0.3 g of an organic compound gave 50 cm^(3) of nitrogen collected at 300 K and 715 mm pressure. Calculate the percentage of nitrogen in the compound. Aqueous tension of water at 300 K is 15 mm.

In Duma's method, 0.3 g of an organic compound gave 50 cm^(3) of nitro

1.	In Duma's method, 0.3 g of an organic compound gave 50 cm^(3) of nitrogen collected at 300 K and 715 mm pressure. Calculate the percentage of nitrogen in the compound. Aqueous tension of water at 300 K is 15 mm.
Answer» Solution :Step I. Volume of `N_(2)` at N.T.P. `{:("EXPERIMENTAL Conditions","N.T.P. Conditions"),(V_(1)=50 cm^(3),V_(2)=?),(P_(1)=715-15=700 mm,P_(2)=760 mm),(T_(1)=300 K,T_(2)=273 K):}` `(P_(1)V_(1))/T_(1)=(P_(2)V_(2))/T_(2)` or `V_(2)=(P_(1)V_(1)T_(2))/(T_(1)P_(2))=((700mm)xx(50 cm^(3))xx(273 K))/((300 K)xx(760 mm))=41.9 cm^(3)` Step II. Percentage of NITROGEN `=28/22400xx("Volume of "N_(2)" at N.T.P.")/("MASS of COMPOUND")xx100=28/22400xx41.9/0.3xx100=17.46 %`