1.

In Duma's method for estimation of nitrogen, 0.25 g of an organic compound gave 40 mLof nitrogen collected at 300 K temperature and 725 mm pressure. If the aqueous tension at 300 K is 25mm, the percentage of nitrogen in the compound is

Answer»

16.76
15.76
17.36
`18.20`

Solution :`V_(1) = 40 mL, V_(2)` at NTP = ?
`P_(1) = 725 - 25 = 700 mm, P_(2) = 760 mm`
`T_(1) = 300 K, T_(2) = 273 K`
`:. V_(2) = (P_(1)V_(1)T_(2))/(P_(2)T_(1)) = (700 xx 40 xx 273)/(760 xx 300) = 33.52 mL`
`%N = (28)/(22400) xx (33.52)/(0.25) xx 100 = 16.76`


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