Saved Bookmarks
| 1. |
In Duma's method for estimation of nitrogen, 0.25 g of an organic compound gave 40 mLof nitrogen collected at 300 K temperature and 725 mm pressure. If the aqueous tension at 300 K is 25mm, the percentage of nitrogen in the compound is |
|
Answer» 16.76 `P_(1) = 725 - 25 = 700 mm, P_(2) = 760 mm` `T_(1) = 300 K, T_(2) = 273 K` `:. V_(2) = (P_(1)V_(1)T_(2))/(P_(2)T_(1)) = (700 xx 40 xx 273)/(760 xx 300) = 33.52 mL` `%N = (28)/(22400) xx (33.52)/(0.25) xx 100 = 16.76` |
|