In Duma's method for estimation of nitrogen, 0.25 g of an organic compound gave 40 mL of nitrogen collected at 300 K temperature and 725 mm pressure. If the aqueous tension at 300 K is 25 mm, the percentage of nitrogen in the compound is

In Duma's method for estimation of nitrogen, 0.25 g of an organic comp

1.	In Duma's method for estimation of nitrogen, 0.25 g of an organic compound gave 40 mL of nitrogen collected at 300 K temperature and 725 mm pressure. If the aqueous tension at 300 K is 25 mm, the percentage of nitrogen in the compound is
Answer» `16.76` `15.76` `17.36` `18.20` Solution :Let us calculate volume of `N_(2)` EVOLVED at N.T.P. Experimental conditions N.T.P. conditions `{:(V_(1)=40 mL,V_(2)=?),(P_(1)=(725-25)=700mm,P_(2)=760 mm),(T_(1)=300 K,T_(2)=273 K):}` Byapplying gas equation : `(P_(1)V_(1))/T_(1)=(P_(2)V_(2))/T_(2)` `V_(2)=(P_(1)V_(1)T_(2))/(P_(2)T_(1))` `V_(2)=((700mm)XX(40 mL)xx(273 K))/((760mm)xx(300 K))` `=33.52 mL` `%` of `N=28/22400xx("Volume of "N_(2)" at N.T.P.")/("Mass of compound")XX100` `=28/22400xx((33.52 mL))/((0.25 g))xx100` `=16.76 %`