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In Dumas' method for estimation of nitrogen, 0.3g of an organic compound gave 50mL of nitrogen collected at 300K temperature and 715 mm pressure. Calculate the percentage composition of nitrogen in the compound. (Aqueous tension at 300K = 15mm) |
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Answer» SOLUTION :Laboratory temperature `=T_(1) = 300K` `:. p_(1) = (715-15) = 700mm` 22400 mL of `N_(2)` at STP weight = 28g Volume of `N_(2)` at STP `= (p_(1)V_(1))/(T_(1)) XX (273)/(760)` `V= (700 xx 50)/(300) xx (273)/(760) mL` = 41.9 mL Mass of `N_(2)` at STP `= (28 xx 41.9)/(22400)` %N `= (28 xx 41.9)/(22400) xx (100)/(m)` `=(28 xx 41.9 xx 100)/(22400 xx 0.3)` = 17.16% OR %N `= (0.0499 xx p_(1)V_(1))/(m T_(1)) = (0.0499 xx 700 xx 50)/(0.3 xx 300)` = 17.46% |
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