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In each of the following pairs of compounds, which one is more covalent and why ? (i) AgCl, AgI (ii) BeCl_(2), MgCl_2 (iii) SnCl_(2), SnCl_(4) (iv) CuO,CuS |
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Answer» Solution :Applying Fajan's rules , the RESULT can be obtained in each CASE as follows : (i) `AgI` is more covalent than `AgCl`. This is because `I^(-)` ion is larger in size than`Cl^(-)` ion and hence `I^(-)` is more polarized than`Cl^(-)`ion. (ii) `BeCl_(2)` is more covalent than `MgCl_(2)`. This is because `Be^(2+)` ion is smallerin size than `MG^(2+)` ion andhence `Be^(2+)` ion has greater polarizing power . (iii) `SnCl_(4)` is more covalent than `SnCl_(2)` . This is because `Sn^(4+)` ion has greater charge and smaller size than `Sn^(2+)` ion and hence `Sn^(4+)` has greater polarizing power. (iv) `CuS` is more covalent than `CuO`. This is because`S^(2-)` ion has larger size than `O^(2-)` ion and hence `S^(2-)` is more polarized than `O^(2-)` ion . |
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