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In each of the four situations of column-I , a stretched string or an organ pipe is given along with the required data. In case of strings the tension in string is T=102.4 N and the mass per unit length of string is 1g/m. Speed of sound in air is 320 m/s. Neglect end corrections.The frequencies of resonance are given in column-II.Match each situation in column-I with the possible resonance frequencies given in Column-II.A. `{:(,p,q,r,s),((A),1,3,2,4):}`B. `{:(,p,q,r,s),((B),1,4,3,2):}`C. `{:(,p,q,r,s),((C ),3,2,4,1):}`D. `{:(,p,q,r,s),((D ),2,4,1,3):}` |
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Answer» (A) The fundamental frequency in the string. `f_0=sqrt(T//mu)/(2l)=sqrt(102.4/(1xx10^-3))xx1/(2xx0.5)Hz=320 Hz`. Other possible resonance frequencies are `f_A and f_0=320 Hz, 640 Hz, 960 Hz` (B)The fundamental frequency in the string. `f_0=sqrt(T//mu)/(4l)=320/(4xx0.5)=160 Hz`. Other possible resonance frequencies are `f_B`=160 Hz, 480 Hz, 800 Hz. (C )The fundamental frequency in both ends open organ pipe is `f_0=v/(2l)=320/(2xx0.5)=320 Hz` Other possible resonance frequencies are `f_c=320 Hz,640 Hz, 960 Hz` (D)The fundamental frequency in one end open organ pipe is `f_0=v/(4l)=320/(4xx0.5)=160 Hz` Other possible resonance frequencies are `f_D=160 Hz, 480 Hz, 800 Hz` |
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