In electrolysis of `NaCl` when `Pt` electrode is taken `H_(2)` is liberated at cathode while `Hg` cathode it forms sodium amalgam becauseA. Hg is more inert than PtB. Na is dissolved in Hg while it does not dissolve in PtC. More voltage is required to reduce `H^(+)` ions at Hg than at PtD. Concentration of `H^(+)` ions is larger when Pt electrode is taken

In electrolysis of `NaCl` when `Pt` electrode is taken `H_(2)` is libe

1.	In electrolysis of `NaCl` when `Pt` electrode is taken `H_(2)` is liberated at cathode while `Hg` cathode it forms sodium amalgam becauseA. Hg is more inert than PtB. Na is dissolved in Hg while it does not dissolve in PtC. More voltage is required to reduce `H^(+)` ions at Hg than at PtD. Concentration of `H^(+)` ions is larger when Pt electrode is taken
Answer» Correct Answer - C

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