InterviewSolution
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InterviewSolution
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In electrolysis of `NaCl` when `Pt` electrode is taken `H_(2)` is liberated at cathode while `Hg` cathode it forms sodium amalgam becauseA. Hg is more inert than PtB. More voltage is required to reduce `H^(+)` at Hg than at PtC. Na is dissolved in Hg while it does not dissolve in PtD. Concentration of `H^(+)` ions is larger when Pt electrode is taken. |
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Answer» Correct Answer - B More voltage is required to reduce `H^(+)` at Hg-cathode than at Pt-cathode. |
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