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In electrolysis of `NaCl` when `Pt` electrode is taken `H_(2)` is liberated at cathode while `Hg` cathode it forms sodium amalgam becauseA. Hg is more inert than PtB. more voltage is required to reduce `H^(+)` at Hg than at PtC. Na is dissolved in Hg while it does not dissove in PtD. concentration of `H^(+)` ions is larger when Pt electrode is taken |
Answer» Correct Answer - D Voltage required to reduce ions changes with the nature of electrode. No `H_(2)` gas is liberated as more voltage is required to reduce `H^(+)` at Hg than at Pt. |
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