InterviewSolution
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InterviewSolution
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In equimolar solution of glucose, NaCl and `BaCl_(2)`, the order of osmotic pressure is as followA. Glucose `gt NaCl gt BaCl_(2)`B. `NaCl gt BaCl_(2)gt` GlucoseC. `BaCl_(2)gt NaCl gt` GlucoseD. Glucose `gt BaCl_(2)gt NaCl` |
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Answer» Correct Answer - C `BaCl_(2)rArr Ba^(2+)+2Cl^(-)=3` ion `NaCl rArr Na^(+)+Cl^(-)=2` ion Glucose `rArr` No ionisation `therefore BaCl_(2)gt NaCl gt` Glucose |
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