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In Exercise 9, let us take theposition of mass when the spring is unstretched as x=0, and the direction from left to right as the positive direction of x-axis. Give x as a function of time t for the oscillating mass if at the moment we start the stopwatch (t=0), the mass is at the maximum compressed position. In what way to these functions for SHM differ from each other, in frequency, in amplitude or the initial phase?

Answer» <html><body><p></p>Solution :Amplitude from exercise : `14.9, A = 2 <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a>` <br/> Angular frequency `omega = sqrt((k)/(m)) = sqrt((1200)/(3)) = sqrt(400) = <a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a> <a href="https://interviewquestions.tuteehub.com/tag/rad-1175618" style="font-weight:bold;" target="_blank" title="Click to know more about RAD">RAD</a> s^(-1)` <br/> Initial phase inthe maximum compressed position `phi = (3pi)/(2) rad` <br/> Displacement of block at time t `x(t) = A <a href="https://interviewquestions.tuteehub.com/tag/sin-1208945" style="font-weight:bold;" target="_blank" title="Click to know more about SIN">SIN</a> (omega t+phi)` <br/> ` = 2sin (2omega t+(3pi)/(2))= -2cos 20 t cm`. <br/> Hence, in all these three <a href="https://interviewquestions.tuteehub.com/tag/cases-910165" style="font-weight:bold;" target="_blank" title="Click to know more about CASES">CASES</a>, amplitude and frequency are same but differ only in initial phase because motions starts from different positions.</body></html>


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