In fcc unit cell the radius of each atom (sphere) is releated to the edge length ( or side) of the cube asA. `r=(sqrt(3))/(2)a`B. `r=(sqrt(3))/(4)a`C. `r=sqrt(3)a`D. `r=(4)/(sqrt(3))`

In fcc unit cell the radius of each atom (sphere) is releated to the e

1.	In fcc unit cell the radius of each atom (sphere) is releated to the edge length ( or side) of the cube asA. `r=(sqrt(3))/(2)a`B. `r=(sqrt(3))/(4)a`C. `r=sqrt(3)a`D. `r=(4)/(sqrt(3))`
Answer» Correct Answer - 2 The length of the body diagonal is equal to `sqrt(3)a` .In bcc unit cell , all the three spheres(atoms) along the diagonal touch each other.therefore ` 4r=sqrt(3a)` `r=(sqrt(3))/(4)a`.

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In fcc unit cell the radius of each atom (sphere) is releated to the edge length ( or side) of the cube asA. `r=(sqrt(3))/(2)a`B. `r=(sqrt(3))/(4)a`C. `r=sqrt(3)a`D. `r=(4)/(sqrt(3))`

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