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:In Fig. 12.15, two circular flower bedshave been shown on two sides of a square lawnABCD of side 56 m. If the centre of each circularlower bed is the point of intersect ion O of thediagonals of the square lawn, find the sum of theareas of the lawn and the flower beds. |
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Answer» total area = area of sector OAB+ area of sector ODC + area of triangle OAD + area of triangle OBC=(90/360 × 22/7 × 28 × 56 + 90/360 × 22/7 × 28 × 56 + 1/4 × 56 × 56 + 1/4 × 56 × 56) m^2=1/4 × 28 × 56( 22/7 + 22/7 + 2 + 2)m^2=7×56/7(22+22+14+14)m^2=56×72 m^2=4032m^2 |
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