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In Fig. 6.130, ABCD is a trapezium, EF || AD and EF || BC. Find the measure of Zxº, Zyº and Zzº.120 de50°Fig. 6.130 |
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Answer» since AD is parallel to BC and AC is transversalthere fore m(dac)=m (ACB)X=50 degree (Alternate Angle)since AD parallel to EF and FD is transversaltherefore y=180-m. (DYE)=180-120=60 degree(interior angles)since AD parallel to EF and AZ is transversal therefore z=xsince x=50therefore z=50 too 💖 y+120°= 180° (internet ang.)y=180-120= 60° z°=50° (alternate ang.) x°=z° (corresponding ang.)x°=50° 50° is the right answer. plz like my answer |
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