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In Fig. 6.15,<PQR = < PRQ, then prove that <PQS = < PRT. |
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Answer» <PQR=<PRQ<PQS=180-<PQR.......{angles on St line<PRT=180-<PRQ.......{angles on St linesince <PQR=<PRQso <PQS=<PRT |
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