1.

In Fig. 6.31,OA . OB = OC . OD.Show that ∠A =∠C and ∠B =∠D.

Answer»

OA . OB = OC . OD (Given)

So, OA/OC=OD/OB ....  (1)

Also, we have AOD =COB (Vertically opposite angles) ...... (2)

Therefore, from (1) and (2), ΔAOD ~  ΔCOB (SAS similarity criterion)

So, A = C and D =B

(Corresponding angles of similar triangles)



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