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In Fig. $ 6.32, $ if $ \mathrm{AB}\left\|\mathrm{CD}, \angle A P Q=50^{\circ} $ and \right.$ \angle \mathrm{PRD}=127^{\circ}, $ find $ x $ and $ y $ |
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Answer» x = 50° ( vertically opposite angle)y + 50° = 127° ( exterior angle theorem)y = 127° - 50°y = 77° |
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