In Fig. $6.36, \frac{Q R}{Q S}=\frac{Q T}{P R}$ and $\angle 1=\angle 2 – InterviewSolution

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1.	In Fig. $6.36, \frac{Q R}{Q S}=\frac{Q T}{P R}$ and $\angle 1=\angle 2 .$ Showthat $\Delta P Q S \sim \Delta$ TOR.
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