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In fig. 6, find the area of the shaded region, enclosed between two concentriccircles of radii 7 cm and 14 cm where 2A0C-40°. (Use π22)Figure 6 |
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Answer» The Area of Major Sector of bigger circle =360 -theta / 360 × 22/7 × r × r360- 40 /360 × 22/7 × 14× 14By solving it you will get answer as, 547.55 cm^2 The Area of major sector of smaller circle =360- theta / 360 × 22/7 × r × r360 - 40 /360 ×22/7×7×7By solving it you will get answer as,136.88cm^2The area of shaded region = area of bigger cicles major sector - area of smaller cicles major sectorArea of shaded region = 547.55 - 136.88= 410.67 cm ^2 Like my answer i you find it useful! |
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