In Fig. 7.222, angle B is greater than 90 degrees and segement AD⊥BC

1.	In Fig. 7.222, angle B is greater than 90 degrees and segement AD⊥BC, show that (i) b2=h2+a2+x2−2ax (ii) b2=a2+c2−2ax
Answer» In Fig. 7.222, angle B is greater than 90 degrees and segement $A D ⊥ B C$ , show that (i) $b^{2} = h^{2} + a^{2} + x^{2} - 2 a x$ (ii) $b^{2} = a^{2} + c^{2} - 2 a x$

In Fig. 7.222, angle B is greater than 90 degrees and segement AD⊥BC, show that (i) b2=h2+a2+x2−2ax (ii) b2=a2+c2−2ax

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In Fig. 7.222, angle B is greater than 90 degrees and segement $A D ⊥ B C$ , show that
(i) $b^{2} = h^{2} + a^{2} + x^{2} - 2 a x$
(ii) $b^{2} = a^{2} + c^{2} - 2 a x$

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In Fig. 7.222, angle B is greater than 90 degrees and segement AD⊥BC, show that (i) b2=h2+a2+x2−2ax (ii) b2=a2+c2−2ax

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