1.

In Fig. 9.9, BOA is a diameter of a circle and the tangent at a point P meets BA extended at T. If ∠PBO = 30°, then ∠PTA is equal to 30°.

Answer»

Solution : True. As ∠BPA = 90°, ∠PAB = ∠OPA = 60°. Also, OP⊥PT. 

Therefore, ∠APT = 30° and ∠PTA = 60° – 30° = 30°.



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