In Fig. 9, is shown a sector OAP of a circle with centre O, containing ∠θ. AB is perpendicular to the radius OA and meets OP produced at B. Prove that the perimeter of shaded region is r[tan θ+sec θ+πθ180−1]

In Fig. 9, is shown a sector OAP of a circle with centre O, containing

1.	In Fig. 9, is shown a sector OAP of a circle with centre O, containing ∠θ. AB is perpendicular to the radius OA and meets OP produced at B. Prove that the perimeter of shaded region is r[tan θ+sec θ+πθ180−1]
Answer» In Fig. 9, is shown a sector OAP of a circle with centre O, containing $∠ θ$ . AB is perpendicular to the radius OA and meets OP produced at B. Prove that the perimeter of shaded region is $r [t a n θ + s e c θ + \frac{π θ}{180} - 1]$

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In Fig. 9, is shown a sector OAP of a circle with centre O, containing ∠θ. AB is perpendicular to the radius OA and meets OP produced at B. Prove that the perimeter of shaded region is r[tan θ+sec θ+πθ180−1]

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