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In Fig. AB and CD are diameters of a circle with centre O. If ∠OBD = 50°, find ∠AOC. |
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Answer» Given that, ∠OBD = 50° Since, AB and CD are the diameters of the circles and O is the centre of the circle Therefore, ∠PBC = 90° (Angle in the semi-circle) ∠OBD + ∠DBC = 90° 50° + ∠DBC = 90° ∠DBC = 40° By degree measure theorem, ∠AOC = 2∠ABC ∠AOC = 2 x 40° = 80° |
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