1.

In Fig. AB and CD are diameters of a circle with centre O. If ∠OBD = 50°, find ∠AOC.

Answer»

Given that, 

∠OBD = 50° 

Since, 

AB and CD are the diameters of the circles and O is the centre of the circle 

Therefore, 

∠PBC = 90° 

(Angle in the semi-circle) 

∠OBD + ∠DBC = 90° 

50° + ∠DBC = 90° 

∠DBC = 40° 

By degree measure theorem, 

∠AOC = 2∠ABC 

∠AOC = 2 x 40° 

= 80°



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