In Fig., AB and CD are parallel lines and transversal EF intersects th

1.	In Fig., AB and CD are parallel lines and transversal EF intersects them at P and Q respectively. If ∠APR = 25°, ∠RQC = 30° and ∠CQF = 65°, thenA. x = 55°, y = 40°B. x = 50°, y = 45°C. x = 60°, y = 35°D. x = 35°, y = 60°
Answer» Given, AB ‖ CD And, EF cuts them So, 30° + 65° + ∠PQR = 180° 95° + ∠PQR = 180° ∠PQR = 85° ∠APQ + ∠PQC = 180°(Co. interior angle) 25° + y + 85° + 30° = 180° y = 40° In ΔPQR ∠PQR + ∠PRQ + ∠QPR = 180° 85° + x + y = 180° x = 55° Thus, x = 55° and y = 40°

In Fig., AB and CD are parallel lines and transversal EF intersects them at P and Q respectively. If ∠APR = 25°, ∠RQC = 30° and ∠CQF = 65°, thenA. x = 55°, y = 40°B. x = 50°, y = 45°C. x = 60°, y = 35°D. x = 35°, y = 60°

Answer»

Given,

AB ‖ CD

And, EF cuts them

So,

30° + 65° + ∠PQR = 180°

95° + ∠PQR = 180°

∠PQR = 85°

∠APQ + ∠PQC = 180°(Co. interior angle)

25° + y + 85° + 30° = 180°

y = 40°

In ΔPQR

∠PQR + ∠PRQ + ∠QPR = 180°

85° + x + y = 180°

x = 55°

Thus,

x = 55° and y = 40°