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In Fig., AB || DE. Find ∠ACD. |
Answer» Since, AB ‖ DE ∠ABC = ∠CDE (Alternate angles) ∠ABC = 40° In ΔABC ∠A + ∠B + ∠ACB = 180° 30° + 40° + ∠ACB = 180° ∠ACB = 180° – 70° = 110° (i) Now, ∠ACD + ∠ACB = 180°(Linear pair) ∠ACD + 110° = 180°[From (i)] ∠ACD = 180° – 110° = 70° Hence, ∠ACD = 70°. |
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