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In Fig,AB II QR . Find the length of PB |
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Answer» We have ΔPAB and ΔPQR ∠P = ∠P(common) ∠PAB = ∠PQR (Corresponding angles) Then, ΔPAB ~ ΔPQR (BY AA similarity) So, \(\frac{PB}{PR}\) =\(\frac{AB}{QR}\) (Corresponding parts of similar triangle area proportion) Or , \(\frac{PB}6\) = \(\frac{3}9\) Or PB = \(\frac{3}9\) x 6 Or PB= 2 cm |
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