In Fig, AD and CF are respectively perpendiculars to sides BC and AB o

1.	In Fig, AD and CF are respectively perpendiculars to sides BC and AB of △ABC. If ∠FCD = 50°, find ∠BAD.
Answer» We know that the sum of all angles of a triangle is 180° Therefore, for the given △FCB, we have ∠FCB + ∠CBF + ∠BFC = 180° 50° + ∠CBF + 90°= 180° ∠CBF = 180° – 50° – 90° = 40° Using the above steps for △ABD, we can say that: ∠ABD + ∠BDA + ∠BAD = 180° ∠BAD = 180° – 90° – 40° = 50°

In Fig, AD and CF are respectively perpendiculars to sides BC and AB of △ABC. If ∠FCD = 50°, find ∠BAD.

Answer»

We know that the sum of all angles of a triangle is 180°

Therefore, for the given △FCB, we have

∠FCB + ∠CBF + ∠BFC = 180°

50° + ∠CBF + 90°= 180°

∠CBF = 180° – 50° – 90° = 40°

Using the above steps for △ABD, we can say that:

∠ABD + ∠BDA + ∠BAD = 180°

∠BAD = 180° – 90° – 40° = 50°