1.

In Fig., AOC is a diameter of the circle and arc AXB = 1/2 arc BYC. Find ∠BOC.

Answer»

As arc AXB = 1/2 arc BYC, 

∠AOB = 1/2 ∠BOC 

Also ∠AOB + ∠BOC = 180º 

Therefore, 1/2 ∠BOC + ∠BOC = 180º

or ∠BOC = 2/3 x 180º = 120º



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