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In Fig., AOC is a diameter of the circle and arc AXB = 1/2 arc BYC. Find ∠BOC. |
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Answer» As arc AXB = 1/2 arc BYC, ∠AOB = 1/2 ∠BOC Also ∠AOB + ∠BOC = 180º Therefore, 1/2 ∠BOC + ∠BOC = 180º or ∠BOC = 2/3 x 180º = 120º |
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