In Fig., BC = CA and ∠A = 40. Then, ∠ACD is equal to(a) 40° (b) 8 – InterviewSolution

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1.

In Fig., BC = CA and ∠A = 40. Then, ∠ACD is equal to(a) 40° (b) 80° (c) 120° (d) 60°

Answer»

(b) 80^o

We know that, the exterior angle is equal to sum of opposite interior angles.

So, ∠ACD = ∠A + ∠B

As ΔACB is isosceles triangle with AC = BC

Therefore, ∠A must be equal to ∠B

∠ACD = 40^o + 40^o

= 80^o

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