In fig. `C_(1) = 20 muF, C_(2) = 30 muF and C_(3) = 15 muF` and the insulated plate of `C_(1)` is at a potential of 90 V, one plate of `C_(3)` being earthed. What is the potential difference between th plates of `C_(2)` three capacitors being connected in series ?A. 10 e.s.u.B. 30 e.s.u.C. 40 e.s.u.D. 20 e.s.u.

In fig. `C_(1) = 20 muF, C_(2) = 30 muF and C_(3) = 15 muF` and the in

1.	In fig. `C_(1) = 20 muF, C_(2) = 30 muF and C_(3) = 15 muF` and the insulated plate of `C_(1)` is at a potential of 90 V, one plate of `C_(3)` being earthed. What is the potential difference between th plates of `C_(2)` three capacitors being connected in series ?A. 10 e.s.u.B. 30 e.s.u.C. 40 e.s.u.D. 20 e.s.u.
Answer» Correct Answer - D `C_(1)=20esu, C_(2)=30esu,C_(3)=15esu,` `V=90esu, V_(2)=?` `1/C_(s)=1/C_(1)+1/C_(2)+1/C_(3)` `=1/20+1/30+1/15=(3+2+4)/60` `C_(s)=60/9esu` Now `V_(2)=Q/C_(2)=(C_(s)*V)/C_(2)=60/9xx90/30` `V_(2)=20esu`

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