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In fig., circles C(O,r) and C(O′,r2) touch internally at a point A and AB is a chord of the circle C (O,r) intersecting C(O′,r2) at C. Prove that AC = CB. [3 MARKS]

Answer»

In fig., circles C(O,r) and C(O,r2) touch internally at a point A and AB is a chord of the circle C (O,r) intersecting C(O,r2) at C. Prove that AC = CB. [3 MARKS]







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