1.

In Fig., if AB || CD, EF || BC, ∠BAC = 65° and ∠DHF = 35°, find ∠AGH.

Answer»

Given,

AB ‖ CD and,

EF ‖ BC

∠BAC = 65° and ∠DHF = 35°

∠BAC = ∠ACD (Alternate angles)

∠ACD = 65°

∠DHF = ∠GHC (Vertically opposite angles)

∠GHC = 35°

In ΔGHC

∠GCH + ∠GHC + ∠HGC = 180°

65° + 35° + ∠HGC = 180°

∠HGC = 80°

∠AGH + ∠HGC = 180°(Linear pair)

∠AGH + 80° = 180°

∠AGH = 100°



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